Calculus · 0606 Topic 14

Differentiation Rules (Product, Quotient, Chain)

Teacher Rig, IGCSE Add Math tutor

Written by Teacher Rig

8 years teaching IGCSE Add Math · Updated 12 June 2026

dydx\frac{dy}{dx} is the gradient function, and three rules extend the power rule (xnnxn1x^n \to nx^{n-1}) to every function 0606 throws at you. Each rule has a written setup that is both error-prevention and the first method mark.

Product rule, y=uvy = uv

(uv)=uv+uv(uv)' = u'v + uv' y=x2sinxy = x^2 \sin x: u=x2u = x^2, u=2xu' = 2x; v=sinxv = \sin x, v=cosxv' = \cos x (the setup line) dydx=2xsinx+x2cosx\frac{dy}{dx} = 2x \sin x + x^2 \cos x

Quotient rule, y=uvy = \frac{u}{v}

(uv)=uvuvv2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2} The numerator’s order is the trap: derivative-of-top times bottom comes FIRST, minus top times derivative-of-bottom. Quote the general formula before substituting, the quoted line survives a sign slip; silent working doesn’t.

y=2x+1x2+3y = \frac{2x + 1}{x^2 + 3}: u=2u' = 2, v=2xv' = 2x dydx=2(x2+3)(2x+1)(2x)(x2+3)2=62x2x2(x2+3)2\frac{dy}{dx} = \frac{2(x^2 + 3) - (2x + 1)(2x)}{(x^2 + 3)^2} = \frac{6 - 2x - 2x^2}{(x^2 + 3)^2}

Simplify the numerator; leave the denominator squared and unexpanded, expanding it wastes time and invites errors.

Chain rule, composite functions

For y=(3x25)4y = (3x^2 - 5)^4: outer derivative ×\times inner derivative:

dydx=4(3x25)3×6x=24x(3x25)3\frac{dy}{dx} = 4(3x^2 - 5)^3 \times \mathbf{6x} = 24x(3x^2 - 5)^3

The forgotten ×6x\times 6x is the chain rule’s signature error. Recognition cue: any function of a function. ()n(\ldots)^n, e()e^{(\ldots)}, ln()\ln(\ldots), sin()\sin(\ldots), chains. The standard derivatives that feed all three rules (none given in the exam): sinxcosx\sin x \to \cos x, cosxsinx\cos x \to -\sin x, tanxsec2x\tan x \to \sec^2 x, exexe^x \to e^x, lnx1x\ln x \to \frac{1}{x}, trig in radians only.

Choosing and combining

Product of two functions \to product rule; ratio \to quotient rule (or rewrite as a product with a negative power); composite \to chain. Hard questions nest them: y=x2e3xy = x^2 e^{3x} is a product whose second factor needs the chain. Work outside-in, one rule per line, naming each (“product rule:”, “chain on e3xe^{3x}:”), the named lines are followable, and followable is markable.

Common mistakes

  • Quotient numerator order flipped
  • Chain rule’s inner derivative dropped
  • Setup lines skipped, every slip then costs full marks
  • Products differentiated term-by-term as if they were sums
  • Degree-mode thinking in trig derivatives

Full topic context: Calculus notes · the full exam drill: differentiation technique.

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