Equations, Inequalities and Graphs · 0606 Topic 4

Solving Cubic Inequalities Graphically

Teacher Rig, IGCSE Add Math tutor

Written by Teacher Rig

8 years teaching IGCSE Add Math · Updated 12 June 2026

A cubic inequality like (x+2)(x1)(x3)>0(x + 2)(x - 1)(x - 3) > 0 cannot be safely solved by sign-rule memory, three factors generate too many cases. The graph does it in seconds, and 0606 expects exactly that method.

The method

Solve (x+2)(x1)(x3)>0(x + 2)(x - 1)(x - 3) > 0.

  1. Roots: x=2,1,3x = -2, 1, 3 (from the factors, or run the cubic factorising routine first if given expanded form).
  2. Sketch: positive x3x^3 coefficient, comes from below-left, ends up-right, weaving through the three crossings.
  3. Read ">0> 0": the curve is above the axis between 2-2 and 11, and after 33. 2<x<1-2 < x < 1 or x>3x > 3

The sketch needs thirty seconds and no scale, just the crossings in order and the end behaviour. Negative x3x^3 coefficient flips the weave (starts up-left, ends down-right); check the sign before drawing, because every region answer depends on it.

Repeated roots change the reading

A squared factor touches the axis instead of crossing:

(x2)2(x+1)>0(x - 2)^2(x + 1) > 0: roots at 1-1 and 22 (double). The curve crosses at 1-1, then touches at 22 without going below. Answer: x>1x > -1, x2x \ne 2, the touch-point itself gives equality, excluded by the strict >>.

That "x2x \ne 2" exclusion is a genuinely tested detail, and only the sketch makes it visible. With \ge, the answer becomes simply x1x \ge -1.

Writing the regions

Same conventions as quadratic inequalities: separate intervals joined by “or”; sandwich notation for bounded regions; strictness following the question’s symbol (strict inequality excludes the roots, non-strict includes them).

Exam connections

These inequalities almost always arrive as the second part of a question whose first part factorised the cubic, a hence chain. Re-deriving the roots from scratch wastes the gift. The same sketch also answers “for what values of kk does p(x)=kp(x) = k have three solutions?”, slide a horizontal line between the local max and min values.

Common mistakes

  • Regions guessed from sign rules instead of drawn
  • End behaviour assumed positive without checking the x3x^3 coefficient
  • Repeated roots drawn as crossings
  • Strict inequalities including the roots (or the touch-point)
  • Three-root cubics answered with a single interval, almost always wrong

Full topic context: Equations, Inequalities & Graphs notes.

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