Permutations and Combinations · 0606 Topic 11

Combinations (nCr)

Teacher Rig, IGCSE Add Math tutor

Written by Teacher Rig

8 years teaching IGCSE Add Math · Updated 12 June 2026

(nr)=n!r!(nr)!\binom{n}{r} = \dfrac{n!}{r!(n-r)!} counts the ways to choose rr items from nn when order is irrelevant, committees, teams, hands of cards, subsets.

Choose 4 students from 10 for a committee: (104)=210\binom{10}{4} = 210.

It’s nPr{}^nP_r with the arrangements divided out (÷r!\div\, r!), which is the intuition: choose-and-arrange, then forget the arranging. Useful symmetry: (nr)=(nnr)\binom{n}{r} = \binom{n}{n-r}, choosing 4 to include is the same as choosing 6 to exclude; (108)\binom{10}{8} computes faster as (102)=45\binom{10}{2} = 45.

Multi-group selections: multiply the choices

The standard exam escalation draws from labelled pools:

A committee of 5 from 6 men and 4 women, with exactly 3 men: (choose the men) ×\times (choose the women) =(63)×(42)=20×6=120= \binom{6}{3} \times \binom{4}{2} = 20 \times 6 = \mathbf{120}

Each group’s selection is independent → multiply. Conditions like “more men than women” split into cases (3M2W, 4M1W, 5M0W), each a product, added, list the cases before computing; the case list is the method.

”At least” / “at most”: count the complement

At least one woman on the committee of 5 from 6M + 4W: Total - none: (105)(65)=2526=246\binom{10}{5} - \binom{6}{5} = 252 - 6 = \mathbf{246}

One subtraction beats four added cases, fewer computations, fewer chances to omit one. State the structure in words (“total minus all-male committees”); the stated logic earns credit even through an arithmetic slip. “At most one” = (none) + (exactly one), still fewer cases from the small side.

Mixed select-then-arrange questions

The harder parts chain combinations into permutations: “choose 4 of 9 books, then arrange them on a shelf” =(94)×4!= \binom{9}{4} \times 4! (=9P4= {}^9P_4, consistency check available). When a question mixes a choice phase with an ordering phase, write the two factors separately and label them.

Common mistakes

  • (nr)\binom{n}{r} where positions are distinguishable (that’s nPr{}^nP_r territory, apply the order test)
  • Case lists missing a case (write them down first)
  • “At least” built case-by-case when the complement was one line
  • Group selections added instead of multiplied
  • Answers left as (63)\binom{6}{3} symbols when a number was asked

Full topic context: P&C notes · the synthesis: arrangements & selections.

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