Straight-Line Graphs · 0606 Topic 7

Area of Rectilinear Figures

Teacher Rig, IGCSE Add Math tutor

Written by Teacher Rig

8 years teaching IGCSE Add Math · Updated 12 June 2026

Given a polygon’s vertices, 0606 expects the shoelace method (the “array” method), fast, general, and worth full marks when two rules are respected: vertices in order, and a modulus at the end.

The array layout

Find the area of triangle A(1,2)A(1, 2), B(5,3)B(5, 3), C(4,7)C(4, 7). Write the coordinates as columns, repeating the first vertex at the end:

| xx: | 11 | 55 | 44 | 11 | | yy: | 22 | 33 | 77 | 22 |

Down-products (xx of one column ×\times yy of the next): 13+57+42=461 \cdot 3 + 5 \cdot 7 + 4 \cdot 2 = 46 Up-products (y×y \times next xx): 25+34+71=292 \cdot 5 + 3 \cdot 4 + 7 \cdot 1 = 29 Area =124629== \tfrac{1}{2}|46 - 29| = 8.58.5

The written array is the method mark, even with one arithmetic slip, the structure scores. It generalises unchanged to quadrilaterals and beyond: more columns, same weave.

The two non-negotiables

Order the vertices around the shape (either direction, but consistently). A crossed ordering. ABDCABDC instead of ABCDABCD, computes the area of a bow-tie, not your quadrilateral, and the error is silent. If the question doesn’t hand you an order, plot the points roughly first; thirty seconds of sketch prevents the most expensive mistake in the subtopic.

Take the modulus and halve. The raw difference is negative when you happened to go clockwise, area is 12difference\tfrac{1}{2}|\text{difference}|, always positive.

Where the vertices come from

Area questions usually sit at the end of a multi-part question: the vertices are intersection points found earlier, a foot of a perpendicular, or points constructed from parallel conditions. Exact coordinates (fractions, surds) go into the array exactly, premature rounding here corrupts the final answer beyond mark-scheme tolerance.

Alternative decompositions (rectangle minus triangles, 12×base×height\tfrac{1}{2} \times \text{base} \times \text{height} with a convenient horizontal side) earn the same marks when valid, but the shoelace is the method that never needs an idea, which is what you want under time pressure.

Common mistakes

  • Vertices unordered (the bow-tie error)
  • First vertex not repeated, so one product pair goes missing
  • Modulus skipped, negative “area” presented
  • The 12\tfrac{1}{2} forgotten
  • Rounded coordinates fed in when exact ones existed

Full topic context: Straight-Line Graphs notes.

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