Permutations and Combinations: worked exam questions

9 solved permutations and combinations questions, each worked line by line the way the 0606 mark scheme rewards. Learn the method in the Permutations and Combinations topic notes, then see it applied here.

Paper 2 5 marks

A Committee with At Least Two Men

Count committees with at least two men by adding the qualifying cases, a 0606 combinations question on handling 'at least' by cases.

Arrangements Around a Circular Table (Beyond 0606)

Count seatings around a round table with (n−1)! and the block method. Extension practice: circular arrangements are not examined in Cambridge 0606.

Arrangements of a Word with Repeated Letters (Beyond 0606)

Count distinct arrangements of the letters of BANANA by dividing n! by the factorials of the repeats. Extension practice: repeated-object cases are not in 0606.

Paper 2 4 marks

Arrangements with a Restriction: Letters Together

Count arrangements of a word where two letters must stay together using the block method, a 0606 permutations question on the 'glue them together' technique.

Paper 2 4 marks

Arrangements with Two People Not Together

Count arrangements where two people must not sit together using the total-minus-together method, a 0606 permutations question on the complement approach.

Paper 2 3 marks

Arrangements: Forming Numbers Without Repetition

How many 4-digit numbers can be formed from seven digits with no repetition, a 0606 permutations question, and why order makes this nPr not nCr.

Paper 2 4 marks

Combinations: Selecting a Committee

Count committees with a fixed number of men and women using the multiplication principle with nCr, a 0606 combinations question on independent selections.

Paper 2 4 marks

Forming Numbers with a Restriction

Count how many 4-digit even numbers can be formed with no repetition, a 0606 permutations question using the 'fill the restricted position first' rule.

Paper 2 4 marks

Selections with an 'At Least One' Condition

Count teams containing at least one woman by subtracting the all-men case from the total, a 0606 combinations question on the complement method.

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