Factors of Polynomials · 0606 Topic 3

Polynomial Long Division

Rig, founder of IGCSE Add Math Malaysia

Written by Rig, our founder

8 years teaching IGCSE & SPM maths · Updated 16 August 2026

Polynomial long division is the bridge between finding one factor of a cubic and factorising it completely. Once the factor theorem gives you a linear factor, dividing by it leaves a quadratic quotient you can factorise the usual way.

The routine

Divide x33x24x+12x^3 - 3x^2 - 4x + 12 by (x2)(x - 2).

Work term by term, highest power first:

  1. x3÷x=x2x^3 \div x = x^2. Multiply back: x2(x2)=x32x2x^2(x - 2) = x^3 - 2x^2. Subtract: (x33x2)(x32x2)=x2(x^3 - 3x^2) - (x^3 - 2x^2) = -x^2.
  2. Bring down: x24x-x^2 - 4x. Now x2÷x=x-x^2 \div x = -x. Multiply back: x(x2)=x2+2x-x(x - 2) = -x^2 + 2x. Subtract: (x24x)(x2+2x)=6x(-x^2 - 4x) - (-x^2 + 2x) = -6x.
  3. Bring down: 6x+12-6x + 12. Now 6x÷x=6-6x \div x = -6. Multiply back: 6(x2)=6x+12-6(x - 2) = -6x + 12. Subtract: 00.

The quotient is x2x6x^2 - x - 6, with remainder 00 (confirming (x2)(x - 2) is a factor): x33x24x+12=(x2)(x2x6)x^3 - 3x^2 - 4x + 12 = (x - 2)(x^2 - x - 6)

Comparing coefficients: the faster alternative

Many students prefer to skip long division and compare coefficients. Write (x2)(x2+bx+c)(x - 2)(x^2 + bx + c), expand, and match: (x2)(x2+bx+c)=x3+(b2)x2+(c2b)x2c(x - 2)(x^2 + bx + c) = x^3 + (b - 2)x^2 + (c - 2b)x - 2c

Matching x33x24x+12x^3 - 3x^2 - 4x + 12: 2c=12c=6-2c = 12 \Rightarrow c = -6; b2=3b=1b - 2 = -3 \Rightarrow b = -1. So the quadratic is x2x6x^2 - x - 6, the same result, often more quickly.

Common mistakes

  • Sign errors when subtracting each partial product (subtracting a negative).
  • Losing a term by not lining up powers (use a 0x0x placeholder if a power is missing).
  • Forgetting to factorise the quadratic quotient afterward when “completely” is asked.

Full topic context: Factors of Polynomials notes, and the worked cubic example.

Keep going

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