Worked Example · Functions · Paper 2 · 6 marks

Range and Why a Function Is Not One-One

Rig, founder of IGCSE Add Math Malaysia

Written by Rig, our founder

8 years teaching IGCSE & SPM maths · Updated 16 August 2026

This question chains three linked ideas the 0606 functions topic loves: reading a maximum from completed-square form, stating a range, and understanding why a parabola is not one-one (and how a domain restriction fixes that).

A function is defined by f(x)=5(x2)2f(x) = 5 - (x - 2)^2 for xRx \in \mathbb{R}. (i) State the greatest value of f(x)f(x) and the value of xx at which it occurs. [2] (ii) State the range of ff. [1] (iii) Explain why ff does not have an inverse, and state the largest value of kk for which ff defined on xkx \le k is one-one. [3]

The working

(i) The expression is already in completed-square form. Since (x2)20(x - 2)^2 \ge 0, subtracting it from 55 makes ff largest when the square is zero: greatest value=5, at x=2(B1, B1)\text{greatest value} = 5, \text{ at } x = 2 \quad \text{(B1, B1)}

(ii) Nothing can be added above 55, and ff decreases without limit as xx moves away from 22: range: f(x)5(B1)\text{range: } f(x) \le 5 \quad \text{(B1)}

(iii) ff is a "\cap"-shaped parabola with vertex at x=2x = 2. Every value below 55 is produced by two xx-values (one each side of x=2x = 2), so ff is many-one and has no inverse over all reals. (B1)

To make it one-one, restrict the domain to one side of the vertex. The largest such interval ending at the vertex is x2x \le 2: k=2(M1, A1)k = 2 \quad \text{(M1, A1)}

Where the marks are won and lost

  • Because (x2)2(x - 2)^2 is subtracted, the vertex is a maximum, not a minimum. Reading it as a minimum flips the range the wrong way.
  • The range is f(x)5f(x) \le 5 (one-sided). Writing f(x)5f(x) \ge 5 is the standard slip for a downward parabola.
  • The one-one explanation must mention two inputs sharing an output (or the horizontal-line idea). “It’s a parabola” alone is not the reasoning the mark rewards.

Common mistakes

  • Treating the vertex as a minimum and giving range f(x)5f(x) \ge 5.
  • Choosing kk on the wrong side, or an interval that still spans the vertex.
  • Saying ff has no inverse “because it’s quadratic” without the many-one reason.

Full method: One-One Functions notes. See also Domain & Range and the Functions pillar.

Common questions

What does one-one mean and why does it matter for inverses?
A function is one-one if every output comes from exactly one input, no horizontal line crosses the graph more than once. A parabola is many-one because each value below its maximum is produced by two different x-values, one each side of the vertex. This matters because only one-one functions have inverses: if two inputs share an output, the reverse process cannot decide which one to return. Restricting the domain to one side of the vertex makes a quadratic one-one, and therefore invertible.

Keep going

See the teaching work on your own child. Then decide.

Every student starts with a 1-hour trial class taught by the vetted tutor your child would actually have. Real teaching, a diagnostic on real exam questions, and a straight answer on the gap to target. One hour at your tutor's rate (RM80–90/hr), no package and no deposit, and you decide afterwards whether to book a weekly slot. Online anywhere in Malaysia.