Worked Example · Functions · Paper 2 · 6 marks
Range and Why a Function Is Not One-One
Written by Rig, our founder
8 years teaching IGCSE & SPM maths · Updated 16 August 2026
This question chains three linked ideas the 0606 functions topic loves: reading a maximum from completed-square form, stating a range, and understanding why a parabola is not one-one (and how a domain restriction fixes that).
A function is defined by for . (i) State the greatest value of and the value of at which it occurs. [2] (ii) State the range of . [1] (iii) Explain why does not have an inverse, and state the largest value of for which defined on is one-one. [3]
The working
(i) The expression is already in completed-square form. Since , subtracting it from makes largest when the square is zero:
(ii) Nothing can be added above , and decreases without limit as moves away from :
(iii) is a ""-shaped parabola with vertex at . Every value below is produced by two -values (one each side of ), so is many-one and has no inverse over all reals. (B1)
To make it one-one, restrict the domain to one side of the vertex. The largest such interval ending at the vertex is :
Where the marks are won and lost
- Because is subtracted, the vertex is a maximum, not a minimum. Reading it as a minimum flips the range the wrong way.
- The range is (one-sided). Writing is the standard slip for a downward parabola.
- The one-one explanation must mention two inputs sharing an output (or the horizontal-line idea). “It’s a parabola” alone is not the reasoning the mark rewards.
Common mistakes
- Treating the vertex as a minimum and giving range .
- Choosing on the wrong side, or an interval that still spans the vertex.
- Saying has no inverse “because it’s quadratic” without the many-one reason.
Full method: One-One Functions notes. See also Domain & Range and the Functions pillar.