Functions: worked exam questions

10 solved functions questions, each worked line by line the way the 0606 mark scheme rewards. Learn the method in the Functions topic notes, then see it applied here.

Paper 1 6 marks

Composite Functions and Solving fg(x) = k

Form fg(x) and gf(x), see why order matters, then solve fg(x) = 21, a 0606 functions question that rewards careful substitution.

Paper 2 4 marks

Domain of a Composite Function

Form a composite involving a square root and find its domain, a 0606 functions question testing which inputs keep the composite defined.

Paper 1 5 marks

Finding an Inverse Function and Its Domain

Find the inverse of f(x) = 3/(x − 2) and state its domain, a 0606 question testing the swap-and-rearrange method and the domain–range link.

Paper 2 4 marks

Inverse of a Rational Function

Find the inverse of a rational function like (2x+1)/(x−3), a 0606 question testing the collect-and-factor step that isolates x.

Paper 2 6 marks

Range and Why a Function Is Not One-One

Find the greatest value and range of 5 − (x − 2)², explain why it is not one-one, and find the domain restriction that makes it invertible, a 0606 functions question.

Paper 2 5 marks

Range of a Composite Function on an Interval

Form a composite function and find its range over a restricted domain, a 0606 functions question combining composition with interval reasoning.

Paper 1 4 marks

Showing a Function Is Self-Inverse

Find the inverse of a rational function and show it equals the original, a 0606 functions question on self-inverse functions where f⁻¹(x) = f(x).

Paper 1 5 marks

Solving a Composite Equation gf(x) = k

Form a composite and solve it equal to a value, a 0606 functions question ending in a square root with two solutions to keep.

Paper 1 5 marks

Solving a Modulus Function Equation

Solve |2x − 6| = 4 by splitting into two cases, and state the range of the modulus function, a 0606 question on |ax + b| the mark scheme wants seen in full.

Paper 1 4 marks

Where a Function Meets Its Inverse

Find where a linear function equals its own inverse, and see why for an increasing function this reduces to solving f(x) = x, a 0606 functions question.

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